[cpp] палиндром-готово
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- #include <iostream>
- #include <string>
- using namespace std;
- int main()
- {
- int t;
- int counter = 0;
- string s;
- cin >> t;
- for (int i = 0; i < t; i++) {
- counter = 0;
- int a, b;
- cin >> a >> b;
- cin >> s;
- for (int j = 0; j < s.length() / 2; j++) {
- if (s[j] != '?' && s[s.length() - j - 1] == '?') s[s.length() - j - 1] = s[j];
- if (s[j] == '?' && s[s.length() - j - 1] != '?') s[j]= s[s.length() - j - 1];
- }
- int a1 = 0, b1 = 0;
- for (int j = 0; j < a + b; j++) {
- if (s[j] == '0') a1++;
- if (s[j] == '1') b1++;
- }
- a1 = a - a1;
- b1 = b - b1;
- if (a1 < 0 || b1 < 0) {
- cout << -1<<endl;
- counter++;
- }
- for (int j = 0; j < (a + b) / 2; j++) {
- if (s[j] == '?' && a1 >= 2) {
- s[j] = '0';
- s[s.length() - j - 1] = '0';
- a1-=2;
- }
- else if (s[j] == '?' && b1 >= 2) {
- s[j] = '1';
- s[s.length() - j - 1] = '1';
- b1-=2;
- }
- }
- if (s.length() % 2 != 0 && a1 == 1) s[(a + b) / 2] = '0';
- if (s.length() % 2 != 0 && b1 == 1) s[(a + b) / 2] = '1';
- for (int i = 0; i < s.length(); i++) {
- if (s[i] == '?' && counter==0) {
- cout << -1<<endl;
- counter++;
- }
- }
- string s1 = s;
- reverse(s.begin(), s.end());
- if (s != s1 && counter == 0) {
- cout << -1 << endl;
- counter++;
- }
- if(counter==0) cout << s1<<endl;
- }
- return 0;
- }
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